please help.. i have only one more attempt A 1.02 times 10-2 kg bullet is fired

Question

please help.. i have only one more attempt

A 1.02 times 10-2 kg bullet is fired horizontally into a 2.52-kg wooden block attached to one end of a massless, horizontal spring (k = 850 N/m). The other end of the spring is fixed in place, and the spring is unstrained initially. The block rests on a horizontal, frictionless surface. The bullet strikes the block perpendicularly and quickly comes to a halt within it. As a result of this completely inelastic collision, the spring is compressed along its axis and causes the block/bullet to oscillate with an amplitude of 0.200 m. What is the speed of the bullet? m/s

Explanation / Answer

conserving momentum 1.02/100 *v=2.53u 0.5*2.53*u^2=0.5*0.2^2*850 u=3.66 v=927.46

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