Use the ideal gas law to derive an expression that has the ratio of volumes on o

Question

Use the ideal gas law to derive an expression that has the ratio of volumes on one side of the equation and the ratio of pressures on the other (initial and intermediate). I got:....... V1/V2 = p2/p1......... .000040412m^3/.000022412m^3 = 184000Pa/102000Pa......... a) Our measured values of volume do not include the volume of air in the connecting plastic tubes. Let us call this value V0. Modify your equation above to include V0 and solve for its value..... **please help will vote lifesaver!!!**

Explanation / Answer

Ideal Gas Law is PV = nRT. Simply solve for V, plug in your values (make sure you convert temperature to Kelvin!), substitute in the gas constant, etc... PV = nRT => V = nRT / P => V = ((7 mol)(0.08206 L*atm/mol K)(273.15 K))/(1 atm) = 156.9 L

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