Beneath the moveable piston in the drawing, 1.5 moles of a monatomic ideal gas i

Question

Beneath the moveable piston in the drawing, 1.5 moles of a monatomic ideal gas is enclosed at 314 K. the initial volume of the gas is 3.0 m^3. the gas is compressed isothermally to a final volume of 1.0 m^3. how much heat is removed from the gas during this process?

Beneath the moveable piston in the drawing, 1.5 moles of a monatomic ideal gas is enclosed at 314 K. the initial volume of the gas is 3.0 m^3. the gas is compressed isothermally to a final volume of 1.0 m^3. how much heat is removed from the gas during this process?

Explanation / Answer

Steady flow equation is: h1+dq/dm+v1^2/2+p1v1=h2+v2^2/2+dw/dm+p2v2 dq/dm=316/n dq/dm=316/1.5 dq/dm=210.66 J Heat=216.66 J

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