A diver is 1.6 meters tall and has a mass of 60kg. a) Appoximating the diver as

Question

A diver is 1.6 meters tall and has a mass of 60kg.

a) Appoximating the diver as a rod of length 1.6m rotating around its center, estimate the diver's rotational inertia when she is stretched out.

b) The diver goes into the tuck position. Appoximating as a solid sphere of radius 0.4m, estimate the diver's new rotational inertia in the tuck position.

c) The diver begins rotating in the position at a rate of 4 revolutions per second. When she stretches out, determine her new rotational speed.

d) Explain why it is easiest for divers to somersault in the tuck position, less easy in the "pike" position (leg straight), and hardest in the "layout" position (body fully extended).

Explanation / Answer

1. The rotational inertia of a rod is given by I= ml^2/12, where m is the mass of the body and l is the lenth of the body. u can get the answer by substituting. 2. The rotational inertia of a uniform solid sphere is I= 2mr^2/5. 3. Due to conservation of angular momentum, I1omega1=I2omega 2. where I1 is the initial moment of inertia, omega1 is the initial velocity and I2 is the final moment of inertia and omega 2 is the final angular velocity

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