Julie throws a ball to her friend Sarah. The ball leaves Julie\'s hand a distanc

Question

Julie throws a ball to her friend Sarah. The ball leaves Julie's hand a distance 1.5 meters above the ground with an initial speed of 19.0 m/s at an angle 47.0 degrees; with respect to the horizontal. Sarah catches the ball 1.5 meters above the ground. 1.What is the horizontal component of the ball

Explanation / Answer

1)horizontal component of velocity= 19cos(47) =12.957 m/s 2)it is at same level so there is no change in potential energy so KE remains the same hence vertical component= -19sin(47) since direction becomes downward=-13.89m/s 3)T=2usin(47)/g=2*13.89/9.8=2.834sec 4) distance =horizontal component*time=12.957*2.83=36.73 m 5)h is horizontal component and v is vertical so h*2.447=36.73 =>h=15m/s v=(2*g*h)^.5 => v=15.96m/s so speed=21.90 m/sec 6)T=2v/g= 3.25 sec so at it takes 1.625 sec for upward and 1.625 downward journey so it has travelled .822 sec in downward journey so, h=.5 *9.8*.822^2 =3.31m hence, height above julie =13-3.31=9.69m

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