A 12,000-N car is raised using a hydraulic lift, which consists of a U-tube with

Question

A 12,000-N car is raised using a hydraulic lift, which consists of a U-tube with arms of unequal areas, filled with oil with a density of 800 kg/m3 and capped at both ends with tight-fitting pistons. The wider arm of the U-tube has a radius of 18.0 cm and the narrower arm has a radius of 5.00 cm. The car rests on the piston on the wider arm of the U-tube. The pistons are initially at the same level. What is the force that must be applied to the smaller piston in order to lift the car after it has been raised 1.20 m? For purposes of this problem, neglect the weight of the pistons. A) 0.954 kN B) 1.88 kN C) 1.96 kN D) 3.67 kN E) 1.20 kN Answer is C, but not sure how this is. Please show work! Thank you!

Explanation / Answer

F1/A1+RHO*G*H=F2/A2 F2/F1=A2/A1=(R2/R1)^2 F2=(5/18)^2*12000+RHO *G*H*A2 =0.954kN+800*10*1.2*3.14*0.18^2 =1.96

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