A rescue plane wants to drop supplies to isolated mountain climbers on a rocky r

Question

A rescue plane wants to drop supplies to isolated mountain climbers on a rocky ridge 235 below.If the plane is traveling horizontally with a speed of 255 (70.8 ), how far in advance of the recipients (horizontal distance) must the goods be dropped?Suppose, instead, that the plane releases the supplies a horizontal distance of 425 in advance of the mountain climbers. What vertical velocity (up or down) should the supplies be given so that they arrive precisely at the climbers' position?With what speed do the supplies land in the latter case?

Explanation / Answer

time package is in the air = sqrt(2 h / g) =

= sqrt(2*235/9.8) = 6.925 seconds

horiz distance = speed * time = 70.8 * 6.925 = 490.3 meters

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