I am doing a ballistic pendulum lab where i shot a dart out of an air gun at a w
ID: 2214018 • Letter: I
Question
I am doing a ballistic pendulum lab where i shot a dart out of an air gun at a wooden block hung from two strings and measured how much the block moved upon impact with the dart. I need to use the conservation of linear momentum to write an equation for the collision between the dart and the target (from just before to just after the collision.) Also an equation for the motion right AFTER the collision (as the target and dart move up and back). DONT PLUG IN NUMBERS. Also what is the velocity of the dart before the collision if the mass of the dart is .70g, mass of block is 148.25g, distance from center of mass to pivot point is .242m and the distance the block traveled upon impact is .0215m. Sorry for the long problem guys but its literally all part of one lab question.Explanation / Answer
let u be the speed of block .7u=(148.25+.7)v momentum equation it travels theta distance .242theta=.0215 mgl(1-costheta)=.5mv^2 KE conservation equation Solve above , equation, u will get the answer, hope u understood it this time :)
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