680 N (150 lbs) skier moving up a 30 degree frictionless incline that is 10 mete

Question

680 N (150 lbs) skier moving up a 30 degree frictionless incline that is 10 meters long. what is the change in potential energy of the skier as she is pulled from the base to the top of a 5 Meter high hill? B) Why is the potential energy positive? Use words and concepts to explain. C) Find the final velocity of a 680N skier at the base of a frictionless hill if she starts out from rest at a point 5 meters above the base. D) Repeat part C for a 900N skier E) Is the kinetic energy at the base of the hill the same for each skier?

Explanation / Answer

a) change in potential energy = 680* 10 = 6800 J b) it is defined relatively c) 6800 = 0.5 * (680/9.8)*v^2 v = 14 m/s d) 900*5 = 0.5(900/9.8)*v^2 v = 9.899 m/s e) depends on their masses ,since they have different masses they have different kinetic energies

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