A 0.28 block on a horizontal frictionless surface is attached to a spring whose

Question

A 0.28 block on a horizontal frictionless surface is attached to a spring whose force constant is 560 . The block is pulled from its equilibrium position at x = 0 to a displacement x = +0.080 and is released from rest. The block then executes simple harmonic motion along the x-axis (horizontal). The displacement of the block at time = 0.7 is closest to: A 0.28 block on a horizontal frictionless surface is attached to a spring whose force constant is 560 . The block is pulled from its equilibrium position at x = 0 to a displacement x = +0.080 and is released from rest. The block then executes simple harmonic motion along the x-axis (horizontal). The displacement of the block at time = 0.7 is closest to: 0.16 0.104 ?8

Explanation / Answer

amplitude of oscillation A = 0.080 w = sqrt(k/m) = 44.72 x(t) = A*cos(wt) at t= 0.7 sec x(t) = 0.080*cos(44.72*0.7) = 0.0794

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