please solve.. An 8.00 g bullet is fired into a 190 g block that is initially at

Question

please solve..

An 8.00 g bullet is fired into a190g block that is initially at rest at the edge of a table of 1.00 m height. The bullet remains in the block, and after the impact the block landsd=2.3m from the bottom of the table. Determine the initial speed of the bullet.
m/s

Explanation / Answer

initail energy of bullet = 0.5*0.008*u^2 [ u is initial velocity] time taken by block to fall 1 m 1 = 0.5*g*t^2 =>t = 0.451 sec horizontal distance covered in this time = v*0.451 [ where v is the initial horizontal velocity of bullet+ block] => v*0.451 = 2.3 =>v =5.091 m/sec Applying conservation of energy 0.5*0.008*u^2 = 0.5 *0.198 * 5.091^2 =>u =25.32 m/sec

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