A horizontal beam 5m long is attached to a vertical wall with a hinge at one end

Question

A horizontal beam 5m long is attached to a vertical wall with a hinge at one end, and a block of weight 550N hangs from the outer end. The beam is supported by a guy wire from its outer end to the wall directly above the beam. (Figure on back page) A) If the tension in the wire is not to exceed 1480N, what is the minimum height (h) above the beam at which it may be fastened to the wall? B) If the wire were now to be fastened at distance of 0.5m below this point in Part A,with the beam remaining horizontal, what would the new tension in the wire be? Ignore the weight of the beam.

Explanation / Answer

1. The problem statement, all variables and given/known data I've already solved the problem, though I didn't understand WHY I took the steps I did; I just want to know why this is the way to solving the problem. Here's the question: In the figure below, a thin horizontal bar AB of negligible weight and length L = 1.9 m is hinged to a vertical wall at A and supported at B by a thin wire BC that makes an angle ? = 42° with the horizontal. A block of weight W = 140 N can be moved anywhere along the bar; its position is defined by the distance x = 1.06 m from the wall to its center of mass. Find (a) the tension in the wire, and the (b) horizontal and (c) vertical components of the force on the bar from the hinge at A 2. Relevant equations ?Fx = max = 0 ?Fy = may = 0 ?t = 0 3. The attempt at a solution a.) Tension in the wire, T : ?t = 0 = Tsin?L - Wblockx T = Wblockxsin?L T = (140N)(1.06m)sin(42°)(1.9m) T = 116.7265 N Now b.) and c.) can be found easily using the other force relations. My question is, why can't you use the force relations instead of the torque relation? I can see that it gives the wrong answer, but WHY does it give the wrong answer if you don't use the torque r

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