An iron block of the mass 1 kg is suspended on a spring with a spring constant e

Question

An iron block of the mass 1 kg is suspended on a spring with a spring constant equal to 130 N/m , and merged into a vessel with 10 liters of water. The mass is displaced by 10 cm from its equilibrium position, and released. 1) How much energy in J has been dissipated by the time the mass comes to a rest? E = J 2) What is the mass of water in the container in kg ? m(water) = kg 3) Assuming that the water with the block are thermally isolated from their surroundings, by how much will their temperature increase? Express your answer in C . You will need the values of the heat capacity: c(water)=4186 J/kg*C , c(iron)=448 J/kg*C . delta T =

Explanation / Answer

dissipated by the time the mass comes to a rest? Answer: .65 J What is the mass of water in the container in kg ? Answer: 10 kg The amount of energy required to change the temperature of the complete system by delta T is E = c(water)*m(water)*delta T + c(iron)*m(iron)*delta T Delta T = E / [ c(water)*m(water) + c(iron)*m(iron) ] = 0.65 / (4186*10 + 448*1) = 1.54 x 10^-5 deg C

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