A bullet of mass 7.30 times 10-3 kg, moving at 1350 m/s impacts a tree stump and

Question

A bullet of mass 7.30 times 10-3 kg, moving at 1350 m/s impacts a tree stump and penetrates 7.00 cm into the wood before coming to rest. (Take the direction of the bullet to be in the positive direction.) Assuming that the acceleration of the bullet is constant, find the force (including direction) exerted by the wood on the bullet. times kN If the same force acted on the bullet and it had the same impact speed but half the mass, how far would it penetrate into the wood? cm Kinematics can be used to find an expression for the acceleration of the bullet. Newton's second law can then be used to relate the stopping force to the bullet's mass and displacement.

Explanation / Answer

v^2-u^2=2as-----------------------1

-1350*1350=2*a*.07

a=-13017857.1413*-10^6

F=ma

7.3*10-3*13*10^6=95*10^3N =95 KN

b) accelaration will double a=26*10^6

from eq 1

s=.035m=3.5cm

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