A bullet with a mass of 11.0 g is fired at a wooden rod that hangs vertically do
ID: 2205079 • Letter: A
Question
A bullet with a mass of 11.0 g is fired at a wooden rod that hangs vertically down from a pivot point that passes through the upper end of the rod. The bullet embeds itself in the exact center of the rod and the rod/bullet system swings up, reaching a maximum angular displacement of 48.0 degrees from the vertical. The rod has a mass of 325 g, a length of 1.50 m, and we can assume the rod rotates without friction about the pivot point. Assume the bullet is traveling horizontally when it hits the rod, and use g = 10.0 m/s2. WHAT IS THE ANGULAR SPEED OF THE ROD/BULLET SYSTEM IMMEDIATELY AFTER COLLISION?Explanation / Answer
.011*V = .336*v',,, also .5*v'^2 = g*(1.5 - 1.5cos48),,,from these equation find v' speed of rod and V speed of bullet,, angular speed v'/.75
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