A Roller coaster car with a of mass 1000 Kg. moves from point A to point B and t

Question

A Roller coaster car with a of mass 1000 Kg. moves from point A to point B and then to point C a) What will be the gravitational potential energy between point B and C respect of point A, what will be the velocity of the car at points B and C about in respect of point A? b) What is the change in potential energy when the car passes from point B to point C? c) Solve parts A and B but take y = 0 at point C as reference point Between Point C and point A there is a distance of 15m Between Point A and point B there is a distance of 10m

Explanation / Answer

(a) As L = 155 feet = 47.24 meter The vertical height of a from b (h) = L x sin40* = 47.24 x 0.64 = 30.37m PE at a = mgh = 1000 x 9.8 x 30.37 = 267821.83 J PE at b = 0 =>delta PE = PE(final) - PE(initial) = -267821.83 J (b) PE at a =0 PE at b = -267821.83 J =>delta PE = PE(final) - PE(initial) = -267821.83 J

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