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Question 1 You collect 500 buccal swabs from a human population and use the tiss

ID: 220351 • Letter: Q

Question

Question 1

You collect 500 buccal swabs from a human population and use the tissue to isolate DNA from each individual you sampled. You then genotype each individual at a single nucleotide polymorphism (SNP) that you presume to be selectively neutral and obtain the following results.

A1A1 = 300

A1A2 = 50

A2A2 = 150

What is the estimated frequency of A1A2 heterozygotes in this population? Round your answer to two decimal places.

Question 2

Using the data from the previous question, calculate the frequency of A1. Round your answer to two decimal places.

Question 3

Using the data from the first question, calculate the frequency of A2A2 homozygotes expected at Hardy-Weinberg equilibrium. Round your answer to two decimal places.

Question 4

Using the data from the first question, calculate the Hardy-Weinberg expected heterozygosity. Round your answer to two decimal places.

Question 5

Using the data from the first question, calculate the inbreeding coefficient for the population you have sampled. Round your answer to two decimal places.

Explanation / Answer

           A1A1 = 300;          A1A2 = 50;      A2A2 = 150.              (500 Sample)

Allele: A1 = 600;    A1 = 50, A2 = 50;          A2 = 300.     ===> Total Allele = 1000

A1 = 600 + 50 = 650,

A1 = 650/ 1000 = 0.65 (Frequency of A1 Allele = 0.65)

A2 = 300 + 50 = 350

A2 = 350/ 1000 = 0.35 (Frequency of A2 Allele= 0.35)

p + q = 1

0.65 + 0.35 = 1 (Hence proved)

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p = 0.65

p2 = 0.4225 (Frequency of A1A1 homozygotes= 0.4225)

q = 0.35

q2 = 0.1225 (Frequency of A2A2 homozygotes= 0.1225)

2pq = 2 * 0.65 * 0.35 = 0.455 (Frequency of A1A2 heterozygotes= 0.455)

P2 + 2PQ + Q2 = 1

0.4225 + 0.1225 + 0.455 = 1 (Hence proved)

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Expected Heterozygote:

2pq = 2 * 0.65 * 0.35 = 0.455

0.455 * 500 = 227.5

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Inbreeding coefficient = # Expected Heterozygotes - # Observed Heterozygotes

                                                          # Expected Heterozygotes

                                   = 227.5 - 50 / 227.5

                                   = 0.7802

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