1. A 0.060kg ball is propelled by a 1.10kg racquet from rest to a speed of 40.0m

Question

1. A 0.060kg ball is propelled by a 1.10kg racquet from rest to a speed of 40.0m/s. If the two objects are in contact for 250ms, calculate the average force exerted by the racquet on the ball. 2. A 60.0kg swimmer stands at the edge of a 200kg boat that is motionless on the water of a lake. If the swimmer dives from the boat in a horizontal direction due east at 8.00m/s, calculate the velocity of the boat if friction between the boat and the water is neglected. 3. A 500kg car traveling due east at 54.0km/h collides head on with a 3000kg van moving at 18.0km/h. If the two vehicles stick to each other as a result of the collision, calculate the velocity of the combined mass. 4. An 18.0g arrow is fired into a 3.00kg pumpkin suspended on a string. The arrow imbeds itself in the pumpkin and makes it move at 1.50m/s due east. Calculate the velocity of the arrow just before it enters the pumpkin.

Explanation / Answer

A .06kg ball goes from rest (0) to 40 m/s. So the change in momentum is mass*velocity (final)- mass*velocity (initial), or in reality just the final mass*velocity, = .06kg*40 m/s=2.4kg-m/s. To find the force, we divide by the time this momentum changes over, or 250ms=.25sec= 2.4/.25=240/25=approx 9.5 Newtons

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