The pulley shown in the figure above is balanced by three forces applied to it.

Question

The pulley shown in the figure above is balanced by three forces applied to it. Force F1=21 N is applied to the inner rim of the pulley of radius R1=40cm, force F2=5N is applied to the middle rim of the pulley or radius R2=1.3m. Force F3 balances forces F1. and F2 and is applied to outer rim of radius R3=1.5m. What is the magnitude and direction of the torque generated by the force? What is the magnitude and direction of the torque generated by the F2 force? What is the magnitude and direction of the torque generated by the F3 force? What is the magnitude of the F3 force?

Explanation / Answer

A)

F1 force =21N

R1=.4m

torque=21*.4Nm=8.4Nm(anticlockwise)

B)

F2=5N

R2=1.3m

torque=5*1.3Nm=6.5Nm(clockwise)

C)

total torque produced=8.4-6.5=1.9Nm (anticlockwise)

torque needed by F3 is 1.9Nm in clockwise direction to balance torque generated F1 and F2

D)

1.9=F3*r

F3=1.9/1.5=1.26N

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.