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In the first part of the experiment, the latent heat of fusion for water is meas

ID: 2201376 • Letter: I

Question

In the first part of the experiment, the latent heat of fusion for water is measured. In this experiment, water, ice, the inner aluminum can, and the aluminum stirrer gain or lose heat energy. There are three temperatures involved: 0oC, Ti (the starting temperature of the water in the calorimeter), and Tf (the final temperature of the water in the calorimeter). Equation 6 can be rewritten [miceLf] + [micecw(Tf - 0oC)] = [mwcw(Ti - Tf)] + [Ccst(Ti - Tf)] Each of the four terms in brackets represents an energy. For each term identify the substance involved. You must answer all the parts of this question correctly to receive credit. A. Ice B. Water in calorimeter C. Calorimeter can and stirrer D. Water from melted ice

Explanation / Answer

the terms are numbered from left. first term is A. it only changed state. second term is D. it is moving from 0C to Tf third is B. moving from Ti to Tf fourth is C. also moving from Ti to Tf

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