A 54 kg skater is standing still in front of a wall. By pushing against the wall

Question

A 54 kg skater is standing still in front of a wall. By pushing against the wall she propels herself backward with a velocity of -1.3 m/s. Her hands are in contact with the wall for 0.80 s. Ignore friction and wind resistance. Find the magnitude and direction of the average force she exerts on the wall (which has the same magnitude, but opposite direction, as the force that the wall applies to her). (Answer in Magnitude & Direction) (Choices for direction: Upward, Opposite the velocity of the skater, the same direction as the velocity of the skater, not enough info to tell)

Explanation / Answer

impulse=momentum ft=mv Force * .8 seconds = 58 kg * 1 m/s f= 58/.8=72.5 kg-m/sec^2= 72.5 Newton she pushes against the wall, direction is normal to the wall

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.