We know that a spherical planet of uniform mass density will have a gravitationa
ID: 2195658 • Letter: W
Question
We know that a spherical planet of uniform mass density will have a gravitational acceleration of g = GM/R2 at the surface, where G = 6.674Explanation / Answer
a)g = GM/R^2 G = (6.674*(10^(-11))) R1 = (6.84*(10^6)) Volume = V = (4/3)*(22/7)*((6.84*(10^6))^3) Density = Mass/V =>Mass = Density * V = (4/3)*(22/7)*((6.84*(10^6))^3)*5150 = M =>g = ((6.674*(10^(-11)))*(4/3)*(22/7)*((6.84*(10^6))^3)*5150)/((6.84*(10^6))^2) = 9.85174 m/s^2 b)g = GM/R^2 G = (6.674*(10^(-11))) R2 = (8.13*(10^5)) Volume = V = (4/3)*(22/7)*((8.13*(10^5))^3) Density = Mass/V =>Mass = Density * V = (4/3)*(22/7)*((8.13*(10^5))^3)*9970 = M =>g = ((4/3)*(22/7)*((8.13*(10^5))^3)*9970*(6.674*(10^(-11))))/((8.13*(10^5))^2) = 2.2669 m/s^2
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.