(a) Calculate the wavelength of light in vacuum that has a frequency of 4.1 104

Question

(a) Calculate the wavelength of light in vacuum that has a frequency of 4.1 104 Hz. answer in m (b) What is its wavelength in benzene? (The index of refraction of benzene is 1.501.) answer in m (c) Calculate the energy of one photon of such light in vacuum. Express the answer in electron volts. answer in eV (d) What is the properties of and effect on the energy of the photon when it enters the benzene? (Select all that apply.) the energy goes down the energy goes up the energy does not change the energy is proportional to the frequency the energy is not proportional to the frequency the energy is inversely proportional to the frequency

Explanation / Answer

(a) (frequency)(wavelength) = speed of light wavelength =speed of light/ frequency wavelength = 3 x10^8 m/s / 4.1 *10^4 s^-1= 7317.07 meters (b) L= c/f= 3*10^8 / 400.132869 MHz = 0.749 m L'/L = n ..therefore L' = 1.124 m (c) E=hv h = planck constant v = nu = frequency = c/(wavelength) c = speed of light = 300x10^6 m/s h = 663x10^-36 J s so for wavelength = 300 nm -> E = h * 300x10^6/(300x10^-9) = 663x10^-21 J

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