A 10.0- shell is traveling horizontally to the right at 25.0 relative to the gro

Question

A 10.0- shell is traveling horizontally to the right at 25.0 relative to the ground when it explodes into two fragments, one of mass 3.00 and the other of mass 7.00 . The lighter fragment goes directly forward, and the explosion releases 1.50 103 of mechanical energy to the fragments. Find the magnitude of the velocity of the heavier fragment relative to the ground just after the explosion. Find the direction of the velocity of the heavier fragment relative to the ground just after the explosion

Explanation / Answer

M*V + m*v = 10*25 (conservation of momentum)

7*V + 3*v = 10*25
.5*7*V^2 + .5*3*v^2 = .5*10*25^2 + 1500 (energy balance)

V =13.66m/s

v =51.46 m/s

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