ll T-Mobile 4:41 PM Allele Frequencies extra credit.docx? Hardy-Weinberg Practic
ID: 219392 • Letter: L
Question
ll T-Mobile 4:41 PM Allele Frequencies extra credit.docx? Hardy-Weinberg Practice Due: Monday, April 2, 2018 Before starting, review the material for chapter 13 in your notes and textbook to familiarize yourself with population genetics and the Hardy-Weinberg principle. Please work through these problems independently instead of in groups. If you have difficulty, please come see me or email me with questions. Show your work for full credit! I need to know how you found your result. The activity is worth a total of 6 points (2 pts. per question). You can turn your completed extra credit in teo me personally, or you can upload it to the dropbox on Carmen. Approximately one in every 3200 US Caucasian newborns have a disease called cystic fibrosis in which the lung tissue is clogged with thick mucus. Afflicted people rarely live to reproductive age. A mutation on a single gene causes cystic fibrosis and it is a recessive allele (c). The normal condition is dominant (C). a) Calculate the frequency of the c allele in the population (i.e. b) Now calculate the frequency of the C allele (i.e., p). c Now that you know the frequency of p and q, calculate the expected frequencies of all three genotypes in the population (CC, Cc, & cc). Show your work. d) How many people in every 10,000 are heterozygous for the recessive allele? Dashboard Calendar ToDo Notifications InboxExplanation / Answer
1 out of every 3200 US Caucasian have CF disease. That is 100/3200 % i.e 0.03125 % have CF.
The frequency of C allele be p and that of c allele is q. Remember 2 basic formulas, p + q = 1 and p2 + 2pq + q2 = 1.
a. As q2 = 0.03125% = 0.0003125, q = 0.01767.
b. p = 1 - q = 1 - 0.01767 = 0.98233
Therefore frequency of C is 98.233 % and c is 1.767%.
c. Frequency of Cc is 2pq = 2 X 0.98233 X 0.01767 = 0.03472 i.e 3.472%.
Frequency of CC is p2 = 0.96497 i.e 96.496%.
Frequency of cc is q2 = 0.000312 i.e 0.0312%.
d. Heterozygous for recessive is Cc. The frequency of Cc is 3.472%. Therefore in 10000 people 347 people will be Heterozygous recessive.
e. The frequency of c allele will increase as the C allele wont be able to survive diarrhea and hence C allele frequency will decrease. As frequency is relative term drecrease in frequency of C allele means increase in frequency of c allele.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.