Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

A block of mass 3.80 kg is pushed up against a wall by a force that makes an ang

ID: 2191139 • Letter: A

Question

A block of mass 3.80 kg is pushed up against a wall by a force that makes an angle of ? = 50.0 angle with the horizontal as shown below. The coefficient of static friction between the block and the wall is 0.278.



(a) Determine the possible values for the magnitude ofPthat allow the block to remain stationary.


P max =


P min

A block of mass 3.80 kg is pushed up against a wall by a force that makes an angle of ? = 50.0½ angle with the horizontal as shown below. The coefficient of static friction between the block and the wall is 0.278. (a) Determine the possible values for the magnitude ofPthat allow the block to remain stationary. P max = P min

Explanation / Answer

A block of mass 3.00 kg is pushed up against a wall by a force P that makes a 50.0° angle with the horizontal. The coefficient of static friction between the block and the wall is 0.250.

a.) Determine the possible values for the magnitude of Pr that allow the block to remain stationary.

b.) Describe what happens if |Pr| has a larger value and what happens if it is smaller.

c.) Repeat parts a.) and b.) assuming the force makes an angle of theta= 13 degrees with the horizontal


answer is

Weight = 3.00x9.81 = 29.43 N down
Vertical component of applied force = Psin50.0° up
maximum frictional force = 0.250Pcos50.0°

At a minimum value of P, friction will be up.
29.43 = Psin50.0° + 0.250Pcos50.0°
29.43 = P(sin50.0° + 0.250cos50.0°)
P = 29.43/(sin50.0° + 0.250cos50.0°)
P = 31.8 N

At a maximum value of P, friction will be down.
29.43 = Psin50.0° - 0.250Pcos50.0°
29.43 = P(sin50.0° - 0.250cos50.0°)
P = 29.43/(sin50.0° - 0.250cos50.0°)
P = 48.6 N

At a minimum value of P, friction will be up.
29.43 = Psin13° + 0.250Pcos13°
29.43 = P(sin13° + 0.250cos13°)
P = 29.43/(sin13° + 0.250cos13°)
P = 63 N

At a maximum value of P, friction will be down.
0.250cos13° > sin13°
Friction is greater than vertical component of P.
There is no maximum value of P.
The block will not slide up when the angle is 13°.

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote