A 1.19kg ball is attached to a horizontal cord of length L =1.19m whose other en
ID: 2190993 • Letter: A
Question
A 1.19kg ball is attached to a horizontal cord of length L =1.19m whose other end is fixed, as shown below.
(a) If the ball is released, what will be its maximum speed?
(b) A peg is located a distance h directly below the point of attachment of the cord. If h = 0.63 L, what will be the speed of the ball when it reaches the top of its circular path about the nail? (m/s)
Well, I know for sure that part a answer is 4.83m/s
However, I am not sure how to do part b.
I tried and I got, 1.48,3.01,and 3.31, but they are all wrong answers..
Please help me..
Explanation / Answer
(a) v = sqrt(2gl) = 4.83m/s Ans (b) mgl - mgh = 0.5mv^2, so v^2 = 9.8(L - 0.63L) x 2 = 8.63, so v = 2.9376m/s Ans. (potential energy of ball in the beginning = potential energy of the ball at the top of its circular path about the nail + kinetic energy of the ball at the top of its circular path about the nail) Ans
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