Just before it is struck by a racket, a tennis ball weighing 0.560 has a velocit

Question

Just before it is struck by a racket, a tennis ball weighing 0.560 has a velocity of (20m/s)i -(4m/s)j. During the 3.00ms that the racket and ball are in contact, the net force on the ball is constant and equal to -(380N)i +(110N)j . A. What is the x-component of the impulse of the net force applied to the ball? = -1.14 Ns B. What is the -component of the impulse of the net force applied to the ball? = .33 Ns C. What is the -component of the final velocity of the ball? D. What is the -component of the final velocity of the ball? I found A and B but having trouble with C and D.

Explanation / Answer

impulse = change in momentum ; C) 0.560(Vx-20) = -1.14 ; Vx=17.96 m/s i ; d) 0.560(Vy+4) = 0.33 ; Vy= - 3.41 m/s j

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