in the figure shown, sliding particle 1, with mass m1 = 0.300 kg, the right with

Question

in the figure shown, sliding particle 1, with mass m1 = 0.300 kg, the right with a speed of 2.oo m / s on a frictionless surface a. When the particle is in the position x = 0 cm, occurrence of a one dimension elastic collision with particle 2 which is at rest. particle 2 has mass m2 = 0.400 kg. When particle 2 hits the wall, which is in the position XW = 70.0 cm, it bounces back without any loss of kinetic energy. a, In which position along the x-axis, measured in cm, then collide particle 2 again particle 1?

Explanation / Answer

Let v1 and v2 be the velocity of m1 and m2 after collision. By conservation of kinetic energy and linear momentum,
(m1*u^2) /2 =(m1*v1^2)/2 + (m2*v2^2)/2

m1*u = m1* v1 + m2*v2

Solving for v1 and v2 , we get ,
v1 = -0.28, v2 = 1.71

Now , let balls collide at a distance y along the left of origin,
y = v1*t and y + 2*xw = v2* t
Solving for y we get, y = 2.74
Thus balls collide at x = -2.74 .

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