A student working 3.0m away from you in a chemistry lab performs an experiment w
ID: 2188720 • Letter: A
Question
A student working 3.0m away from you in a chemistry lab performs an experiment which creates a bad odor. It takes a while for the smell to get to you (air currents negligible). You are able to move 2.0m further away from the source but the smell catches up with you in another 60 seconds. What is the diffusion coefficient in the air for the molecules you smell?Explanation / Answer
= 6Dt = 6Dt 25 = 6Dt Now, we know that the time it takes to travel three meters is 60s, however, this is NOT a linear rate. We can put the time "t" into two terms, though. 25 = 6D(t1 + t2) We know that one of the times is 60, which will be denoted t2 25 = 6D(t1 + 60) We also known that the time it takes to travel 3m can be represented by way of = 6Dt = 6Dt1 9 = 6Dt1 => D = 1.5/t1 D is a constant, so we can use this information to do a variable cancellation in the first equation via substitution or elimination. I will use substitution. 25 = 6(t1 +60)D 25= 6*t1*D + 360*D 25= 6*t1*1.5/t1 + [360(1.5)]/t1 25 = 9 + 540/t1 16 = 540/t1 t1 = 33.75s Using this information back in the previous equation... 9 = 6Dt1 D = 9/6t1 D = 9/6(33.75) D = 0.044m^2*s^-1 Which is meters squared per second.Related Questions
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