= Two crates connected by a rope of negligible mass lie on a horizontal surface.

Question

=
Two crates connected by a rope of negligible mass lie on a horizontal surface. (See the figure.) Crate A has mass m A and crate B has mass m B. The coefficient of kinetic friction between each crate and the surface is mu k. The crates are pulled to the right at a constant velocity of 3.2 {m/s} by a horizontal force over right arrow F. Part A In terms of m A, m B, and mu k, calculate the magnitude of the force over right arrow F. F = Part B In terms of m A, m B, and mu k, calculate the tension in the rope connecting the blocks. T =

Explanation / Answer

constant velocity means no acceleration then by Newton's law F=(Ma+Mb)uk*g then as for mass A F=uk*g*Ma+T then T=Mb*uk*g consistent, as for mass B T=Mb*uk*g

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