A child\'s game involves shooting a block of mass M toward a target by having it

Question

A child's game involves shooting a block of mass M toward a target by having it slide down a frictionless, straight ramp, and then up and off the end of a second ramp. The target is a horizontal distance (d) equal to 3.6 m from the end of the second ramp. When the block is released a height (h1) equal to 2.6 m above the base of the ramps, it falls short of the target by .8 m. How high (h2) above the base of the ramps should the block be released so that it just hits the target? Neglect any effects of air resistance.

Explanation / Answer

let the velocity v should be needed to travell 3.6 m when it leaves second ramp v(2H/g)^0.5 = 3.6-0.8 v={(2.6-H)2g}^0.5 H=2.395m

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