Three identical 9.40 masses are hung by three identical springs, as shown in the

Question

Three identical 9.40 masses are hung by three identical springs, as shown in the figure. Each spring has a force constant of 5.90 and was 16.0long before any masses were attached to it.How long is each spring when hanging as shown? (Hint: First isolate only the bottom mass. Then treat the bottom two masses as a system. Finally, treat all three masses as a system.)(Figure 1)

Part A. What is the bottom of the spring in meters.

Part B. What is the Middle spring in meters.

Part C. What is the Top Spring in Meters.

Please explain how to do as well (not only solution), much appreciated and thank you.

Explanation / Answer

as given in the question assume bottom most spring to be fixed to the ceiling at top and calculate the weight attached to it 9.4*g=kx where x is the elongation in the spring x=15.61 m and total length of bottom spring= 31.61 m for the middle spring the total weight is 2*9.4=18.8 kg 18.8*g=kx' x'=31.22 m and total length of middle spring is 47.22 m and similarly length of topmost spring =62.8 m

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