1.) Two blocks are sliding along a frictionless track. Block A (mass 4.81 kg) is

Question

1.) Two blocks are sliding along a frictionless track. Block A (mass 4.81 kg) is moving to the right at 2.40 m/s. Block B (mass 5.77 kg) is moving to the left at 2.88 m/s. Assume the system to be both Block A and Block B.
What is the total momentum of the system before the collision?

Left? Right?

2.) What is the total momentum of the system after the collision?

Left? Right?

3.) The two blocks stick together and move off together. What is the magnitude and direction of the velocity of the blocks after the collision?

Left? Right?

Explanation / Answer

momentum = m1v1 + m2v2 assuming right side as positive direction, = P= 4.81X 2.40 + 5.77 X (-2.88) = -5.073. left aftter collision, the total momentum remains same as the collision is elastic. left if the two blocks collide and stick together, m1v1 + m2v2 =[m1 + m2] V V= -0.479 on the left hand side.

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