We consider the following three electron transitions in a hydrogen atom between

Question

We consider the following three electron transitions in a hydrogen atom between the initial state n and the final state n'.

1) n=1 and n'=3
2) n=6 and n'=4
3) n=7 and n'=2

A) For each of these transitions, which is higher, the initial state energy or the final state energy electrons?

B) Which of these transitions is an emission? Which of these is an absorption?

C) Calculate the magnitude of the transition energies (in eV) and the wave length (in nm) for each of these transitions. In what region of the electromagnetic spectrum are these transitions?

Explanation / Answer

Energy=-13.6/n^2 [n=state number] so when n is greater energy is greater so A) n'=3(final) n=6(initial) n=7(initial) B)emmision : 2,3 absorption : 1 C) 1. E=-13.6 +13.6/9=-12.09 ev 2. E=-13.6/36+13.6/16=.472 ev 3. E=-13.6/49 +13.6/4=3.1222 ev

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