The radius of Mercury (from the center to just above the atmosphere) is 2440 km

Question

The radius of Mercury (from the center to just above the atmosphere) is 2440 km (2440multiplied by103 m), and its mass is 0.3multiplied by1024 kg. An object is launched straight up from just above the atmosphere of Mercury.

a. What initial speed is needed so that when the object is far from Mercury its final speed is 1500 m/s?
Vescape=_________ m/s

b.What initial speed is needed so that when the object is far from Mercury its final speed is 0 m/s? (This is called the "escape speed.")
Vescape = ________ m/s

Explanation / Answer

on solving the above question the answer comes out to be equal to (a)4319.6 m/s (b)4050.8 m/s

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