In part (a) of the figure below, both batteries have emf = 1.40 Vand the externa
ID: 2182143 • Letter: I
Question
In part (a) of the figure below, both batteries have emf = 1.40 Vand the external resistance R is a variable resistor. Part (b) of the figure gives the electric potentials V between the terminals of each battery as functions of R: Curve 1 corresponds to battery 1 and curve 2 corresponds to battery 2. The horizontal scale is set by Rs = 0.20 ?. What is the internal resistance of each; battery 1 and battery 2?
Explanation / Answer
for graph 1, at R = Rs/2, current in the circuit = 0.41/(0.2/2) = 4.1 A so, internal resistance of the battery 1, r1 = (1.4 - 0.41)/4.1 = 0.24 ohmRelated Questions
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