A particle has a charge of q = +4.6 ?C and is located at the origin. As the draw

Question

A particle has a charge of q = +4.6 ?C and is located at the origin. As the drawing shows, an electric field of Ex = +206 N/C exists along the +x axis. A magnetic field also exists, and its x and y components are Bx = +1.9 T and By = +1.2 T. Calculate the force (magnitude and direction) exerted on the particle by each of the three fields when it is (a) stationary, (b) moving along the +x axis at a speed of 345 m/s, and (c) moving along the +z axis at a speed of 345 m/s.


(a) FE =
FBx =
FBy =
(b) FE =
FBx =
FBy =
(c) FE =
FBx =
FBy =

Explanation / Answer

stationary => no magnetic field is acting on it =>9.476x10^-4 +x direction. b) electric = same as before and FBx = 0 and due to FBz = along +z direction = 1.9x10^-3 c) electric is same as above and FBx = 3x10^-3 along -y direction, FBy = 1.9x10^-3 along +x direction

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.