A hungry 725 -N bear walks out on a beam in an attempt to retrieve some \"goodie

Question

A hungry 725 -N bear walks out on a beam in an attempt to retrieve some "goodies" hanging at the end (Fig. P8.20). The beam is uniform, weighs 250 N, and is 8.00-m long; the goodies weigh 70 N. (a) Draw a free-body diagram for the beam. Which picture below is closest to the correct one?

b)When the bear is at x = 1.00 m, find the tension in the wire and the components of the reaction force at the hinge (left side of beam).(Tension, horizontal force on hinge, vertical force on hinge)
c)If the wire can withstand a maximum tension of 849.9 N, what is the maximum distance the bear can walk before the wire breaks?

Explanation / Answer

bear 725 N, beam 250 N, 8 m long, basket 70 N, =60o

-725*1-250*8/2-70*8+T*8*sin()=0, it won't let me draw

b) T=(725+1000+560)/8*sin()329.8 N

Horizontal force =-T*cos(120o)-329.8*-0.5164.91 N right

Vertical force =-725-250-70+T*sin()=0

-1045+285.63=0

Vertical force=759.4 N up

c) 8*[849.9*sin()-250/2+70]/7257.51 m

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.