However, after the crate is in motion, a horizontal force of 58 N is required to

Question

However, after the crate is in motion, a horizontal force of 58 N is required to keep it moving with a constant speed. Find the coefficients of static and kinetic friction between crate and floor.

?static ______
?kinetic ______

Explanation / Answer

Since the crate weighs 24kg, you can find the normal force: Fn = ma --> Normal Force = (24)(9.8) --> Normal Force = 235.2 N The force used to set the box in motion is the applied force against the static friction holding the box in place. To find the static friction coefficient you do this: Applied Force = µs(Normal Force) 75 / 235.2 = µs(235.3) / 235.2 µs = .3188 Static friction coefficient = .3188 The second applied force is less because it has overcome the static friction and is now being acted on by the kinetic friction: Applied Force = µk(Normal Force) 58 = µk(235.2) µk = .246 Kinetic friction coefficient = .246

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