Block A with mass 0.050 kg is released from rest at the rim of a frictionless he

Question

Block A with mass 0.050 kg is released from rest at the rim of a frictionless hemispherical bowl that has radius R = 0.600 m. Block A slides down the side of the bowl and strikes block B, which has mass 0.150 kg and that is sitting at rest at the bottom of the bowl, and the two blocks stick together.

a) What is the speed of the combined object (blocks A and B stuck together) immediately after the collision?

b) What maximum vertical distance above the bottom of the bowl will the combined object reach after the collision?

Explanation / Answer

a) mu^2 /2 = mgR

u = 3.43 m/s

momentim conservation,

0.050 x 3.43 = (0.50 + 0.150)v

v = 0.858 m/s

b) mgh = mv2 /2

h = 0.0375 m

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