A Bar Suspended by Two Vertical Strings The figure shows a model of a crane that

Question

A Bar Suspended by Two Vertical Strings The figure shows a model of a crane that may be mounted on a truck.A rigid uniform horizontal bar of mass = 100.0 and length = 6.000 is supported by two vertical massless strings. String A is attached at a distance = 1.100 from the left end of the bar and is connected to the top plate. String B is attached to the left end of the bar and is connected to the floor. An object of mass = 3500 is supported by the crane at a distance = 5.800 from the left end of the bar. Throughout this problem, positive torque is counterclockwise and use 9.807 for the magnitude of the acceleration due to gravity.

Explanation / Answer

torque balancing at left end(T=tention in a. T'=tention inb) T*1.1-100*9.807*3-3500*9.807*5.8=0t=183658.3636N balancing forces T=110g+3500g+T' T'=148255.0936

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