The following information may be useful in solving this problem e = 1.6 X 10^-29

Question

The following information may be useful in solving this problem e = 1.6 X 10^-29 C. The mass of a chloride ion is approximately 5.9 X 10^-26 kg.
A thin circular sheet of glass of diameter 3 meters is rubbed with a cloth on one surface and becomes charged uniformly. A chloride ion (a chlorine atom that has gained on electron) passes near the glass sheet. When the chloride ion is near the center of the sheet, at a location 0.8 mm from the sheet, it experiences an acceleration of 8.47 x 10^10 m/s^2 toward the sheet.
A) Determine the magnitude and direction of the electric field at the location of the chloride ion.

Explanation / Answer

Let V be the velocity when it reaches the surface v = ?2as = 11.64 X 10^ 3.conserving energy ; Change in potential energy = Change in potential energy ===> P = 1/2m(V^2 - u^2) = 1/2mV^2 = 4 X 10^22 J potential difference = Potential energy/q = 4 X 10^22/-1.6 X 10^-29 = - 2.49 X 10^51 J/C

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