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Two identical boxes of mass 2.00 kg are linked by a string passing over a pulley

ID: 2178549 • Letter: T

Question

Two identical boxes of mass 2.00 kg are linked by a string passing over a pulley, as in the figure. One box is on a horizontal surface, while the other is on an incline in the shape of a 3-4-5 triangle. Assume the string remains taut at all times. Use g = 9.80 m/s2.


(a) If the surfaces are frictionless, what is the acceleration of the system?



(b) If, instead, the boxes are moving at constant velocity so the box on the horizontal surface is moving right, and the box on the slope is moving down the slope, what is the coefficient of kinetic friction between each box and the surface?


For the first one I got it was 2.94m/s^2 but for part b I keep gettin Fn=0 which is not gives me that the Ff is 0... can anyone help me?

Explanation / Answer

for part b mg*sin(theta)-mu*mg*cos(theta)-T=0 T=mu*mg mu=sin(theta)/(1+cos(theta)) mu=1/3=0.33

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