With what acceleration will it move down the same plane inclined at a larger ang

Question

With what acceleration will it move down the same plane inclined at a larger angle, theta ? A block slides with constant velocity down a plane inclined at angle alpha to the horizontal. If the block is projected up the same plane with initial velocity, v0, how far up the plane will it move before stopping ? An engineer who weighs 160 lb stands on a platform that weighs 80 lb. She pulls a rope fastened to the platform and running over a pulley on the ceiling. What force must she exert to give the platform (and herself on the platform) an upward acceleration of 2.0 ft/s2 ? A block weighing 5 lb, connected to an unknown weight, w, is observed to slide down a 530 inclined plane with an acceleration 4 ft/s2. When weight w is doubled, the block slides up the plane with acceleration 4 ft/s2. (see diagram to the right) Calculate weight w. What is the coefficient of sliding friction between the block and the plane ? A block of mass 200 gm rests on top of a mass 800 gm. The combination moves at constant velocity on a level surface with a hanging mass of 200 gm (see diagram).

Explanation / Answer

first condition mgsin(theta)-mgcos(theta)*coefficant of friction - T = ma T- wg = wa adding equation mgsin(theta)-mgcos(theta)*coefficant of friction - wg = ma + wa mgsin(theta)-mgcos(theta)*coefficant of friction - wg = (m+w)*4 second condition mgsin(theta)-mgcos(theta)*coefficant of friction - 2wg = -(m+2w)*4 equation 1 -2 wg = (2m+3w)*4 w=0.9lb putiing w value in equation one coeffciant of friction = 0.78

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