horizontal force of magnitude F on the ball as it drops, show that the ball foll
ID: 2177279 • Letter: H
Question
horizontal force of magnitude F on the ball as it drops, show that the ball follows a straight-line path. Does this mean that the ball falls with constant velocity? Explain. If the ball is dropped with an initial nonzero vertical velocity of vo, will it still follow the path of a straight line? Explain. Using m = 10.0 kg, h = 10.0 m, F = 20 N, and vo = 4.0 m/sec downwards, how far from the building will the ball hit the ground? The three blocks shown (10.0 kg, 5.0 kg, and 3.0 kg, respectively) are connected by massless strings that pass over frictionless pulleys. The acceleration of the system is 2.35 m/s2 to the left and the surfaces are rough. Find the tensions in the strings and the coefficient of kinetic friction between blocks and surfaces (assume mu is same for both blocks) In the figure shown, the coefficient of kinetic friction between the 2.0 kg and the 3.0 kg blocks is 0.30. The horizontal surface and the pulleys are frictionless and the masses are released from rest. Draw a FBD of each block. Determine the acceleration of each block. Find the tension in the strings.Explanation / Answer
given a =2.35 Forces on m1 = m1g, T1(tension in left string) so m1g - T1 = m1a 10g - T1 = 10(2.35) Forces on m2 = T1, T2(tension in right string) , uN (due to friction) (N = m2g) so T1 - T2 - um2g = m2a T1 - T2 - u(5g) = 5(2.35) Forces on m3 = m3g sin25 , T2, uN1 (force die to friction) (N1 = m3gcos25) so T2 - m3gsin25 - um3gcos25 = m3a T2- 3gsin25 - u(3gcos25) = 3(2.35) solving 3 equations we get T1= 74.5 N T2= 34.72 N u = 0.572
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