A student bikes to school by traveling first = 0.900 miles north, then = 0.300 m

Question

A student bikes to school by traveling first = 0.900 miles north, then = 0.300 miles west, and finally = 0.200 miles south. If a bird were to start out from the origin (where the student starts) and fly directly (in a straight line) to the school, what distance would the bird cover? I understand that north cancels south so it would be .7 but when i see it solved by other people they get .72 all of a sudden. And when i look at the steps online it tells me to do the square root of .7^2+-.3^2 which i understand but when i do it i get .64031 rather than the actual answer.Can some please do this step by step I don really care for the answer more for the process.

Explanation / Answer

use Pythagorus theorem, the kid travelled 0.7 (0.9-0.2) miles north and 0.3 miles west, the distance is equal to: C^2= A^2 +B^2 C^2= 0.7^2 + 0.3^2 C^2 = 0.49+0.9 C^2 = 0.58 C = sqrt(0.58) C= 0.81 miles

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