Work on a Block Sliding Up a Frictionless Incline Work on a Block Sliding Up a F

Question

Work on a Block Sliding Up a Frictionless Incline Work on a Block Sliding Up a Frictionless Incline
Part A Express your answer numerically in joules. SubmitHintsMyAnswersGiveUpReviewPart Part B Express your answer numerically in joules. SubmitHintsMyAnswersGiveUpReviewPart Part C Express your answer numerically in joules. SubmitHintsMyAnswersGiveUpReviewPart Part D Express your answer numerically in joules. SubmitHintsMyAnswersGiveUpReview Work on a Block Sliding Up a Frictionless Incline A block of weight= 35.0sits on a frictionless inclined plane, which makes an angle= 21.0with respect to the horizontal, as shown in the figure.(Figure 1)A force of magnitude= 12.5, applied parallel to the incline, is just sufficient to pull the block up the plane atconstant speed. Work on a Block Sliding Up a Frictionless Incline A block of weight= 35.0sits on a frictionless inclined plane, which makes an angle= 21.0with respect to the horizontal, as shown in the figure.(Figure 1)A force of magnitude= 12.5, applied parallel to the incline, is just sufficient to pull the block up the plane atconstant speed.
Part A The block movesup an incline with constant speed. What is the total workdone on the block by all forces as the block moves a distance= 4.30up the incline? Include only the work done after the block has started moving at constant speed, not the work needed to start the block moving from rest. Express your answer numerically in joules. = SubmitHintsMyAnswersGiveUpReviewPart Part B What is, the work done on the block by the force of gravityas the block moves a distance= 4.30up the incline? Express your answer numerically in joules. = SubmitHintsMyAnswersGiveUpReviewPart Part C What is, the work done on the block by the applied forceas the block moves a distance= 4.30up the incline? Express your answer numerically in joules. = SubmitHintsMyAnswersGiveUpReviewPart Part D What is, the work done on the block by the normal force as the block moves a distance= 4.30up the inclined plane? Express your answer numerically in joules. = SubmitHintsMyAnswersGiveUpReview

Explanation / Answer

work=force x displacement caused by the force = 12.5 x 4.30 =53.75 Nm

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.