As the driver steps on the gas pedal, a car of mass 1 180 kg accelerates from re

Question

As the driver steps on the gas pedal, a car of mass 1 180 kg accelerates from rest. During the first few seconds of motion, the car's acceleration increases with time according to the expression below, where t is in seconds and a is in m/s2. a = 1.14 t - 0.210 t2 + 0.240 t3 What is the change in kinetic energy of the car during the interval from t = 0 to t = 1.50 s? 67300 Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. J What is the minimum average power output of the engine over this time interval? 20300

Explanation / Answer

v=(1.14t-0.21t2+0.24t3)dt

integrating from 0 to 1.5

v=1.35

initial v=0

so changee in K.E=1180*1.352/2=1075.275 J

2)P=K.E/t=1075.275/1.5 =716.85 W

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