?l ) irtwo peas AA band aa BB are seised, resulting incedy1%ofth . n peogeny bei
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?l ) irtwo peas AA band aa BB are seised, resulting incedy1%ofth . n peogeny being "th, would you conchde regarding the T and R genes? (A) These two genes are likely () These two genes (C) These are linked, with a genetie distance of 1 eM. two genes are linked, with a genetic distance of 2 cM (D) These two genes are linked, with a genetic distance of 10 cM (E) These two genes are linked, with a genetic distance of 20cM 12) Why was Mendel successfiul in getting the pea experimental results and proposing the two laws which were confirmed later on? (A) Mendel made sure those seven traits were not sex linked (B) Mendel was smart because he followed the progeny of several generations and came out with a model that could his explained his results (C) Mendel was lucky because he chose the pea plants with those seven traits which turned out to be controlled by independently assorted genes (D) B and C are correct (E) All of the above. 2. (6 points) Two diploid strawberry plants were thought to be homozygous for two genes controlling fruit flavor (high vs. low quality) and color (orange vs. yellow): one, high q orange; and the other, low quality and yellow. In order to determine the patterns of their inheritance, these two plants were c following F2 progeny: 225 high quality, orange: 80 high quality, yellow; 35 low quality, orange uality and ross-fertilized and the FI was self-crossed, resulting in the esult, draw a conclusion and 80 low quality, yellow. How would you analyze this inheritance patterns and critical values of the 1 distribution may be helpful. give the genotypes of these two original parents? The following table of p-value 0.9 0.5 0.1 0.05 0.016 0.455 2.706 3.841 6.635 0.211 1.386 4.605 5.991 7.378 0.584 2.366 6.251 7.815 11345 1.064 3.357 7.779 9.488 13.277 1.610 4.351 9.236 11.070 15.086Explanation / Answer
11. The answer is C. These two genes are linked, with a genetic distance of 2 cM.
If the genes are assorted indepently, the double recessieve proprotion will be 1/16 = app. 6%, so the first option is wrong.
The Distance between genes = Total number of recombinants/Total number of progeny X 100.
The distance between genes = % of recombination. If Distance is 1 cM, the % of recombination = 1%, as recombinant category contains two genotyeps, the proportion of each genotype = 1/2 = 0.5%, so, this option B also wrong.
The Distance between genes = Total number of recombinants/Total number of progeny X 100.
The distance between genes = % of recombination. If Distance is 2 cM, the % of recombination = 2%, as recombinant category contains two genotyeps, the proportion of each genotype = 2/2 = 1%, so, this option C is correct.
12. The answer is D. B and C.
According to chegg guidelines we have to answer one question at a time.So, post the rest as seperate questions then I can help you.
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